44m^2+96m=0

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Solution for 44m^2+96m=0 equation: 



44m^2+96m=0

a = 44; b = 96; c = 0;
Δ = b2-4ac
Δ = 962-4·44·0
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$


$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-96}{2*44}=\frac{-192}{88}
=-2+2/11
$


$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+96}{2*44}=\frac{0}{88}
=0
$

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